convertir un in en chaine de caracteres

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Voici le code du itoa de VC++ 6

void xtoa (unsigned long val, char *buf, unsigned radix, int is_neg)
{
    char *p;                /* pointer to traverse string */
    char *firstdig;         /* pointer to first digit */
    char temp;              /* temp char */
    unsigned digval;        /* value of digit */

    p = buf;

    if (is_neg) {
        *p++ = '-';
        val = (unsigned long)(-(long)val);
    }

    firstdig = p;

    do {
        digval = (unsigned) (val % radix);
        val /= radix;

        if (digval > 9)
            *p++ = (char) (digval - 10 + 'a');
        else
            *p++ = (char) (digval + '0');
    } while (val > 0);

    *p-- = '\0';

    do {
        temp = *p;
        *p = *firstdig;
        *firstdig = temp;
        --p;
        ++firstdig;
    } while (firstdig < p);
}

inline char *itoa (char *buf, int val, int radix)
{
    if (radix == 10 && val < 0) xtoa((unsigned long)val, buf, radix, 1);
    else xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
    return buf;
}

C++ (@++)