PROG QUI DONNE LA DATE DU LENDEMAIN

#include<stdio.h>
main(){
       int j,m,a,nbj;
       printf("quelle est la date d'aujourd'hui: ");
       scanf("%d %d %d",&j,&m,&a);
       switch(m){
                 case 1:
                 case 3:
                 case 5:
                 case 7:
                 case 8:
                 case 10:
                 case 12:nbj =31;
                      break;
                 case 4:
                 case 6:
                 case 11:nbj =30;
                      break;
                 case 2:if(a%4==0) nbj=29;
                        else nbj =28;
                      break;
       }
       if(j==nbj){
                  if(m==12){
                            j =1;
                            m =1;
                            a =a+1;
                  }
                  else{
                       j =1;
                       m++;
                  }
       }
       else j++;
       if(j>nbj||m>12) printf("abruti(e)");
       else printf("demain nous serons le: %d %d %d",j,m,a);
       getch();
}